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Whats 9 + 10?

whats 9 + 10


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BitoBain

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Q.A bunny hops 3 times, What is the circumference of the sun?

(A:21)
[sarcasm]
3 bunny hops=2.2m on average
2.2m=6.2m^2 of vegetation trampled assuming it's an average size bunny.
To understand how hard the bunny tramples the plants, use the kinematic equation for final velocity.
vf^2=vi^2+2deltaax
vf^2=0m/s+2(-9.8m/s^2)(2.2m)
vf=6.57m/s
The average # of plants trampled in a bunny pasture is known as Hop's constant: 16.20562
We have to find the derivative of the above kinematic equation to find the average number of plants being trampled at a single moment.
Using the exponent rule, we can conclude that the equation is now 2vf=2vi+2
Thus, the bunny's downward velocity at 1, when it begins touching the plants, is 1.922 m/s, combined with a forward velocity of 6.57m/s. Using the pythagorean theorem, the tangent velocity when it comes into contact with the plants is 6.845ms
Finally, to discover the breaking point of plants found in common bunny habitats, we apply planck's constant and avogadro's number.

Substitute and simplify! eZ!
From there we can conclude that plant growth's limitations are as follows.
W=17.s m^2/d
T=14.6c
At this point, the sunlight variable is the only unknown. Simply solve for h.

This is assuming a planck-size particle is emitting light, to do this we must take into account the distance of the sun from Earth, Earth's size, yearly rotation, and average filtration because of our atmosphere.



Therefore, the diameter of Earth is 1.41 x10^6km
And the circumfrence of the sun is 4 373 032 km.
[/sarcasm]
 
Last edited:

Cimmy

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[sarcasm]
3 bunny hops=2.2m on average
2.2m=6.2m^2 of vegetation trampled assuming it's an average size bunny.
To understand how hard the bunny tramples the plants, use the kinematic equation for final velocity.
vf^2=vi^2+2deltaax
vf^2=0m/s+2(-9.8m/s^2)(2.2m)
vf=6.57m/s
The average # of plants trampled in a bunny pasture is known as Hop's constant: 16.20562
We have to find the derivative of the above kinematic equation to find the average number of plants being trampled at a single moment.
Using the exponent rule, we can conclude that the equation is now 2vf=2vi+2
Thus, the bunny's downward velocity at 1, when it begins touching the plants, is 1.922 m/s, combined with a forward velocity of 6.57m/s. Using the pythagorean theorem, the tangent velocity when it comes into contact with the plants is 6.845ms
Finally, to discover the breaking point of plants found in common bunny habitats, we apply planck's constant and avogadro's number.

Substitute and simplify! eZ!
From there we can conclude that plant growth's limitations are as follows.
W=17.s m^2/d
T=14.6c
At this point, the sunlight variable is the only unknown. Simply solve for h.

This is assuming a planck-size particle is emitting light, to do this we must take into account the distance of the sun from Earth, Earth's size, yearly rotation, and average filtration because of our atmosphere.



Therefore, the diameter of Earth is 1.41 x10^6km
And the circumfrence is 4 373 032 km.
[/sarcasm]
What the actual hell please god I don't want to do this in the future
 

GibbyMC

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[sarcasm]
3 bunny hops=2.2m on average
2.2m=6.2m^2 of vegetation trampled assuming it's an average size bunny.
To understand how hard the bunny tramples the plants, use the kinematic equation for final velocity.
vf^2=vi^2+2deltaax
vf^2=0m/s+2(-9.8m/s^2)(2.2m)
vf=6.57m/s
The average # of plants trampled in a bunny pasture is known as Hop's constant: 16.20562
We have to find the derivative of the above kinematic equation to find the average number of plants being trampled at a single moment.
Using the exponent rule, we can conclude that the equation is now 2vf=2vi+2
Thus, the bunny's downward velocity at 1, when it begins touching the plants, is 1.922 m/s, combined with a forward velocity of 6.57m/s. Using the pythagorean theorem, the tangent velocity when it comes into contact with the plants is 6.845ms
Finally, to discover the breaking point of plants found in common bunny habitats, we apply planck's constant and avogadro's number.

Substitute and simplify! eZ!
From there we can conclude that plant growth's limitations are as follows.
W=17.s m^2/d
T=14.6c
At this point, the sunlight variable is the only unknown. Simply solve for h.

This is assuming a planck-size particle is emitting light, to do this we must take into account the distance of the sun from Earth, Earth's size, yearly rotation, and average filtration because of our atmosphere.



Therefore, the diameter of Earth is 1.41 x10^6km
And the circumfrence is 4 373 032 km.
[/sarcasm]
You have too much time on your hands.
 

OhFancy

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I actually love this vine so much.

"You stupid"
"No I not"
"What's 9+10?"
"twenny wun"

I absolutely died.
 

RedMarzBarz_

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[sarcasm]
3 bunny hops=2.2m on average
2.2m=6.2m^2 of vegetation trampled assuming it's an average size bunny.
To understand how hard the bunny tramples the plants, use the kinematic equation for final velocity.
vf^2=vi^2+2deltaax
vf^2=0m/s+2(-9.8m/s^2)(2.2m)
vf=6.57m/s
The average # of plants trampled in a bunny pasture is known as Hop's constant: 16.20562
We have to find the derivative of the above kinematic equation to find the average number of plants being trampled at a single moment.
Using the exponent rule, we can conclude that the equation is now 2vf=2vi+2
Thus, the bunny's downward velocity at 1, when it begins touching the plants, is 1.922 m/s, combined with a forward velocity of 6.57m/s. Using the pythagorean theorem, the tangent velocity when it comes into contact with the plants is 6.845ms
Finally, to discover the breaking point of plants found in common bunny habitats, we apply planck's constant and avogadro's number.

Substitute and simplify! eZ!
From there we can conclude that plant growth's limitations are as follows.
W=17.s m^2/d
T=14.6c
At this point, the sunlight variable is the only unknown. Simply solve for h.

This is assuming a planck-size particle is emitting light, to do this we must take into account the distance of the sun from Earth, Earth's size, yearly rotation, and average filtration because of our atmosphere.



Therefore, the diameter of Earth is 1.41 x10^6km
And the circumfrence is 4 373 032 km.
[/sarcasm]
Again I'm only a simple 12vie I don't understand this stuff. .-.
 

GibbyMC

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All my teachers get really annoyed because I keep asking them what 9 plus 10 is
 

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